document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=682827>Question 682827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help in this problem, thank you <BR>\n" );
document.write( "Sue took her collection of nickels and dimes to deposit in the bank. She has five fewer nickels than dimes. Her total deposit was $55.40. How many dimes did she deposit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423557 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .05x + .1y = 55.40   &#8658; x is nickles and y is dimes<BR>\n" );
document.write( "x = y-5  &#8658; less nickles, more dimes<BR>\n" );
document.write( ".05(y-5) + .1y = 55.40 &#8658; substituting and solving for y as the question asks for dimes ye<BR>\n" );
document.write( ".05y - .25 + .1y = 55.40<BR>\n" );
document.write( ".15y = 55.40 + .25<BR>\n" );
document.write( ".15y = 55.65<BR>\n" );
document.write( "y = 371 dimes<BR>\n" );
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