Algebra.Com's Answer #423519 by MathTherapy(10555)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
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document.write( "Please help me solve this question
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document.write( "Evaluate: 
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document.write( "I have started it but I'm not sure if I'm doing it right or how to continue.This is what I have:\r
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document.write( "log8^(2(x+2))=log16^(x-2)
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document.write( "2(x+2)log8= (x-2)log16
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document.write( "2xlog8 + 4log8 = xlog16 - 2log16
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document.write( "2xlog8 - xlog16 = -4log8 - 2log16\r
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document.write( "I don't know how to continue from here, can you please help me complete it, and tell me how you got from one step to the next. Thank you.\r
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document.write( "Convert to a similar base, which in this case is: base 2\r
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document.write( "With bases being similar, exponents are too. Therefore, 6(x + 2) = 4(x - 2)\r
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document.write( "6x + 12 = 4x - 8\r
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document.write( "6x - 4x = - 8 - 12\r
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document.write( "2x = - 20\r
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document.write( " , or  \r
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" );
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