document.write( "Question 683336: if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form? \n" ); document.write( "

Algebra.Com's Answer #423518 by fcabanski(1391) $\"\"$ $\"About$

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If the roots of the equation were 3 and 5, the factors would be x-3 and x-5 and the equation would be the product of the factors = (x-3)(x-5) = x^2 -8x +15.

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\n" ); document.write( "x-(-2+sqrt(6)) and x - (-2-sqrt(6)) = x+2-sqrt(6) and x+2+sqrt(6). To find the equation multiply those factors together (multiply each term of the second factor by each term of the first factor).

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