document.write( "Question 683200: solve -2sin^2x=3sinx+1 for exact solutions over the interval [0,2π]
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Algebra.Com's Answer #423488 by jsmallt9(3758)\"\" \"About 
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\"-2sin%5E2%28x%29=3sin%28x%29%2B1\"
\n" ); document.write( "\"exact solutions\" is code for: This problem involves special angles and we should put away our calculators.

\n" ); document.write( "First we want to transform the equation into one or more equations of the form:
\n" ); document.write( "TrigFunction(expression) = number
\n" ); document.write( "This equation is in quadratic form for sin(x). So we'll start by getting one side to be zero. Adding \"2sin%5E2%28x%29\" to each side:
\n" ); document.write( "\"0+=+2sin%5E2%28x%29%2B3sin%28x%29%2B1+\"
\n" ); document.write( "Now we factor. This factors fairly easily. If you have trouble seeing this then use a temporary variable:
\n" ); document.write( "Let q = sin(x). Then the equation becomes:
\n" ); document.write( "\"0+=+2q%5E2%2B3q%2B1\"
\n" ); document.write( "After you factor it replace the q's with sin(x)'s and you'll get:

\n" ); document.write( "\"0+=+%282sin%28x%29%2B1%29%28sin%28x%29%2B1%29+\"
\n" ); document.write( "From the Zero Product Property:
\n" ); document.write( "2sin(x) + 1 = 0 or sin(x) + 1 = 0
\n" ); document.write( "Solving these for sin(x) we get:
\n" ); document.write( "sin(x) = -1/2 or sin(x) = -1
\n" ); document.write( "These equations are in the desired form.

\n" ); document.write( "Next we find the general solution. As anticipated we have special angle values for sin in both equations. For sin(x) = -1/2 we should recognize the reference angle of \"pi%2F6\" has a sin of 1/2. And since sin is negative in the 3rd and 4th quadrants our general solution for this equation is:
\n" ); document.write( "\"x+=+pi%2Bpi%2F6%2B2pi%2An\" for the 3rd quadrant angles
\n" ); document.write( "\"x+=+-pi%2F6%2B2pi%2An\" (or \"2pi-pi%2F6%2B2pi%2An\") for the 4th quadrant angles
\n" ); document.write( "These simplify to:
\n" ); document.write( "\"x+=+7pi%2F6%2B2pi%2An\" for the 3rd quadrant angles
\n" ); document.write( "\"x+=+-pi%2F6%2B2pi%2An\" (or \"11pi%2F6%2B2pi%2An\") for the 4th quadrant angles

\n" ); document.write( "For the equation sin(x) = -1 we should know that only \"3pi%2F2\" (and co-terminal angles) will have a sin of -1. So the general solution for this is:
\n" ); document.write( "\"x+=+3pi%2F2%2B2pi%2An\"
\n" ); document.write( "These three general solution equations express the infinite set of angles that fit your equation.

\n" ); document.write( "Your problem asks for solutions over the interval [0,2π]. For this we use the general solution equations and replace the n's with integers until we find all the x's in the given interval.
\n" ); document.write( "For the equation \"x+=+7pi%2F6%2B2pi%2An\":
\n" ); document.write( "If n = 0 then x = \"7pi%2F6\"
\n" ); document.write( "If n = 1 (or other positive integers, x is greater than \"2pi\"
\n" ); document.write( "If n = -1 (or other negative integers, x is below 0
\n" ); document.write( "For the equation \"x+=+-pi%2F6%2B2pi%2An\"
\n" ); document.write( "If n = 0 (or any negative integer, x is below 0
\n" ); document.write( "If n = 1 then x = \"11pi%2F6\"
\n" ); document.write( "If n = 2 (or larger positive integers, x is greater than \"2pi\"
\n" ); document.write( "For the equation \"x+=+3pi%2F2%2B2pi%2An\"
\n" ); document.write( "If n = 0 then x is below \"3pi%2F2\"
\n" ); document.write( "If n = 1 (or other positive integers, x is greater than \"2pi\"
\n" ); document.write( "If n = -1 (or other negative integers, x is below 0
\n" ); document.write( "So there are only three solutions in the interval [0,2π]: \"7pi%2F6\", \"11pi%2F6\" and \"3pi%2F2\"
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