document.write( "Question 683115: Please solve equation for x over the interval [0°,360°). {{3sectheta-2√3=0}}
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Algebra.Com's Answer #423485 by jsmallt9(3758)\"\" \"About 
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\"3sec%28theta%29-2sqrt%283%29=0\"
\n" ); document.write( "First, isolate the function. Adding \"2sqrt%283%29\":
\n" ); document.write( "\"3sec%28theta%29=2sqrt%283%29\"
\n" ); document.write( "And divide by 3:
\n" ); document.write( "\"sec%28theta%29=2sqrt%283%29%2F3\"
\n" ); document.write( "Perhaps if you know your special angle values very well you might recognize that the right side is a special angle value for sec. If not, then we can convert this to cos. Since cos and sec are reciprocals of each other then if
\n" ); document.write( "\"sec%28theta%29=2sqrt%283%29%2F3\"
\n" ); document.write( "then
\n" ); document.write( "\"cos%28theta%29=3%2F%282sqrt%283%29%29\"
\n" ); document.write( "Rationalizing the right side:
\n" ); document.write( "\"cos%28theta%29=%283%2F%282sqrt%283%29%29%29%28sqrt%283%29%2Fsqrt%283%29%29\"
\n" ); document.write( "\"cos%28theta%29=%283sqrt%283%29%29%2F%282%2A3%29\"
\n" ); document.write( "\"cos%28theta%29=sqrt%283%29%2F2\"
\n" ); document.write( "This is obviously a special angle value for cos. The references angle whose cos is \"sqrt%283%29%2F2\" is 30. Since cos (and sec) are positive in the 1st and 4th quadrants we get a general solution of:
\n" ); document.write( "\"theta+=+30+%2B+360n\"
\n" ); document.write( "\"theta+=+-30+%2B+350n\"
\n" ); document.write( "This general solution expresses the infinite number of values for \"theta\" that are solutions to your original equation.

\n" ); document.write( "Your problem asks for solutions over the interval [0, 360). For these solutions we take the general solution equations and replace the n's with integers until we are satisfied we have found all the \"theta\"'s in the interval.
\n" ); document.write( "From the equation:
\n" ); document.write( "\"theta+=+30+%2B+360n\"
\n" ); document.write( "if n = 0 then \"theta+=+30\"
\n" ); document.write( "if n = 1 (or higher integers), \"theta\" is more than 360.
\n" ); document.write( "if n = -1 (or any other negative integer), \"theta\" is below 0.
\n" ); document.write( "From the equation:
\n" ); document.write( "\"theta+=+-30+%2B+360n\"
\n" ); document.write( "if n = 0 (or any negative integer), \"theta\" is below 0.
\n" ); document.write( "if n = 1, \"theta\" is 330.
\n" ); document.write( "if n = 2 (or higher integers), \"theta\" is more than 360.
\n" ); document.write( "So the only solutions over the interval [0, 360) are 30 and 330.
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