document.write( "Question 61512: Use calculus to determine the relative extrema of f(x)=x-lnx\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the tangent line at x=1\r
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Algebra.Com's Answer #42344 by venugopalramana(3286)\"\" \"About 
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Use calculus to determine the relative extrema of
\n" ); document.write( " f(x)=x-lnx
\n" ); document.write( "DF/DX =1-1/X = 0 AT EXTREMUM
\n" ); document.write( "X =1
\n" ); document.write( "D^F/DX^2 = 1/X^2 = 1/1=+VE
\n" ); document.write( "HENCE X=1 IS A MINIMUM
\n" ); document.write( "SLOPE OF TANGENT AT X=1 DY/DX AT X=1........THAT IS M = 0\r
\n" ); document.write( "\n" ); document.write( "AT X=1 ..Y = 1-LN1 =1
\n" ); document.write( "HENCE EQN.OF TANGENT AT X=1,Y=1 IS
\n" ); document.write( "Y-1=M(X-1)=0
\n" ); document.write( "Y = 1 IS THE EQN. OF THE TANGENT AT X=1\r
\n" ); document.write( "\n" ); document.write( "Find the equation of the tangent line at x=1
\n" ); document.write( "please help, i'm so confused!
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