document.write( "Question 683040: use a calculator to approximate two values of theta ( 0 less than or equal to theta less than 2pi ) that satisfy the equation. round the value to three decimal places.
\n" ); document.write( "1.) cos theta= -0.3214 \r
\n" ); document.write( "\n" ); document.write( "find the indicated trigonometric value in the specified quadrant.
\n" ); document.write( "1.) Function
\n" ); document.write( " sec theta = -9/4
\n" ); document.write( " Quadrant 3
\n" ); document.write( " trigonometric value : tan theta \n" ); document.write( "
Algebra.Com's Answer #423439 by stanbon(75887)\"\" \"About 
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use a calculator to approximate two values of theta ( 0 less than or equal to theta less than 2pi ) that satisfy the equation. round the value to three decimal places.
\n" ); document.write( "1.) cos(theta) = -0.3214
\n" ); document.write( "Note: cos is negative in QII and QII
\n" ); document.write( "cos^-1(-0.3214) = 1.8980 in QII
\n" ); document.write( "Or
\n" ); document.write( "cos^-1(-0.3214) = 4.3852 in QIII
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\n" ); document.write( "find the indicated trigonometric value in the specified quadrant.
\n" ); document.write( "1.) Function
\n" ); document.write( "sec theta = -9/4
\n" ); document.write( "Quadrant 3
\n" ); document.write( "sec = r/x, so r = 9 and x = -4
\n" ); document.write( "Then y = sqrt[r^2-x^2] = sqrt[81-15] = sqrt[66]
\n" ); document.write( "----
\n" ); document.write( "trigonometric value : tan(theta) = y/x = sqrt(66)/4, since x and y are
\n" ); document.write( "negative in QIII
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
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