document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=683020>Question 683020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tickets to the Valentine Dance cost $3 per person or $5 per couple. If $475 worth of tickets were sold and 180 people attended the dance, how many couples were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423431 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let p = number of single persons<BR>\n" );
document.write( "Let c = number of couples<BR>\n" );
document.write( "Then you have two equations, one for amount of sales and one for the number of attendees.<BR>\n" );
document.write( "(1) 3p + 5c = 475 and<BR>\n" );
document.write( "(2) p + 2c = 180<BR>\n" );
document.write( "Solve (2) for p and substitute it into (1) to yield<BR>\n" );
document.write( "(3) 3(180 - 2c) +5c = 475 or<BR>\n" );
document.write( "(4) 540 - 6c + 5c = 475 or<BR>\n" );
document.write( "(5) c = 540 - 475 or<BR>\n" );
document.write( "(6) c = 65.<BR>\n" );
document.write( "Put (6) into (2) and get<BR>\n" );
document.write( "(7) p + 2*65 = 180 or<BR>\n" );
document.write( "(8) p = 180 - 130 or<BR>\n" );
document.write( "(9) p = 50<BR>\n" );
document.write( "Let's use (1) to check the numbers.<BR>\n" );
document.write( "Is (3*50 + 5*65 = 475)?<BR>\n" );
document.write( "Is (150 + 325 = 475)?<BR>\n" );
document.write( "Is (475 = 475)? Yes<BR>\n" );
document.write( "Answer: There were 65 couples that attended the Valentine Dance. </SPAN>\n" );
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