document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61515>Question 61515</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0536821445/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> find the area inside the square,but outside the circle,given that the radius of the circle is 2ft.use 3.14 for  pi. height is 6ft and width is 6ft. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42343 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of the Square=height times width =36 sq ft<BR>\n" );
document.write( "Area of the circle = Pi times radius squared =(3.14)(4)=12.56 sq ft\r<BR>\n" );
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document.write( "Now, in order to find the area inside the square but outside the circle, we simply subtract the area of the circle from the area of the square, or\r<BR>\n" );
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document.write( "36-12.56=23.44 sq ft\r<BR>\n" );
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document.write( "Hope this helps ----ptaylor </SPAN>\n" );
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