document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=683004>Question 683004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A crew of four practices rowing up a river, then back down for the same distance. The current of the river is 3 km/hr. Currently the crew can can row at 15 km/hr in still water and makes the round trip in 25 minutes. How far upstream did they row? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423428 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let distance be x\r<BR>\n" );
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document.write( "upstream speed = 15-3=12 mi/h<BR>\n" );
document.write( "downstream speed = 15+3=18 mi/h\r<BR>\n" );
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document.write( "Time upstream + time downstream = 25 minutes= 25/60 = 5/12 hours\r<BR>\n" );
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document.write( "t=d/r<BR>\n" );
document.write( "x/12 + x/18 = 5/12\r<BR>\n" );
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document.write( "LCD = 36<BR>\n" );
document.write( "multiply equation by 36\r<BR>\n" );
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document.write( "3x+2x=15<BR>\n" );
document.write( "5x=15<BR>\n" );
document.write( "x=3 miles\r<BR>\n" );
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document.write( " </SPAN>\n" );
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