document.write( "Question 682825: if f(x)=ax^2+2a and f(3)-f(1)=60, what is the value of a? \n" ); document.write( "
Algebra.Com's Answer #423359 by jim_thompson5910(35256)\"\" \"About 
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f(x)=ax^2+2a\r
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\n" ); document.write( "\n" ); document.write( "f(3)=a(3)^2+2a\r
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\n" ); document.write( "\n" ); document.write( "f(3)=a*9+2a\r
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\n" ); document.write( "\n" ); document.write( "f(3)=9a+2a\r
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\n" ); document.write( "\n" ); document.write( "f(3)=11a\r
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\n" ); document.write( "\n" ); document.write( "f(x)=ax^2+2a\r
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\n" ); document.write( "\n" ); document.write( "f(1)=a(1)^2+2a\r
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\n" ); document.write( "\n" ); document.write( "f(1)=a*1+2a\r
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\n" ); document.write( "\n" ); document.write( "f(1)=1a+2a\r
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\n" ); document.write( "\n" ); document.write( "f(1)=3a\r
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\n" ); document.write( "\n" ); document.write( "f(3)-f(1)=60\r
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\n" ); document.write( "\n" ); document.write( "11a - 3a = 60\r
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\n" ); document.write( "\n" ); document.write( "8a = 60\r
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\n" ); document.write( "\n" ); document.write( "a = 60/8\r
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\n" ); document.write( "\n" ); document.write( "a = 15/2
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