document.write( "Question 682764: please help me solve this equation. Solve the equation for x over the interval [0,2pi) {{4cos2x=squareroot3}} \n" ); document.write( "

Algebra.Com's Answer #423350 by lwsshak3(11628) $\"\"$ $\"About$

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please help me solve this equation. Solve the equation for x over the interval [0,2pi) {{4cos2x=squareroot3}}
\n" ); document.write( "4cos(2x)=√3
\n" ); document.write( "cos(2x)=√3/4
\n" ); document.write( "Identity: cos(2x)=1-2sin^2x
\n" ); document.write( "1-2sin^2x=√3/4
\n" ); document.write( "2sin^2x=1-√3/4=(4-√3)/4
\n" ); document.write( "sin^2x=(4-√3)/8≈.2835
\n" ); document.write( "sinx=√.2835=≈.5324
\n" ); document.write( "using calculator set to radians
\n" ); document.write( "x=0.5685 and 2.5801 (in Q1 and Q2 where sin>0) \n" ); document.write( "

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