document.write( "Question 682824: Thank you for the help, i need it, thank you, thank you. \r
\n" ); document.write( "\n" ); document.write( "Alexander and Judy are 31 miles apart on a calm lake paddling toward each other.
\n" ); document.write( "Alexander paddles at 5 miles per hour, while Judy paddles at 8 miles per hour. How long will it take them to meet?
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Algebra.Com's Answer #423347 by funmath(2933)\"\" \"About 
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Alexander and Judy are 31 miles apart on a calm lake paddling toward each other.
\n" ); document.write( "Alexander paddles at 5 miles per hour, while Judy paddles at 8 miles per hour. How long will it take them to meet?\r
\n" ); document.write( "\n" ); document.write( "Assuming that they left at the same time: Distance = rate*time
\n" ); document.write( "Let t = time in hours
\n" ); document.write( "Alexander's distance: 5t
\n" ); document.write( "Judy's distance: 8t
\n" ); document.write( "total distance: 31
\n" ); document.write( "\"5t%2B8t=31\"
\n" ); document.write( "\"13t=31\"
\n" ); document.write( "\"t=31%2F13\"
\n" ); document.write( "t= 2.3846 hours
\n" ); document.write( "or
\n" ); document.write( "t= 2hrs+60(.3846)mins
\n" ); document.write( "t=2hrs and 23 mins\r
\n" ); document.write( "\n" ); document.write( "Barring any fatal careless errors, that should be it.
\n" ); document.write( "Happy Calculating!!!
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