document.write( "Question 7648: Clyde took a taxi 1/4 of the distance to Bonnie's house and a bus for 1/3 of the distance to her house. Finally, he walked the remaining 5 miles to her house. How many miles did Clyde travel in total?\r
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Algebra.Com's Answer #4233 by prince_abubu(198)\"\" \"About 
You can put this solution on YOUR website!
Let's call the total distance D. 1/4 of the distance would be \"+%281%2F4%29D+\". The next 1/3 of the distance is \"+%281%2F3%29D+\", and after both distances are covered, there are 5 miles to go. So, just add up the three distances and they all should equal D:\r
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\n" ); document.write( "\n" ); document.write( "\"+%281%2F4%29D+%2B+%281%2F3%29D+%2B+5+=+D+\" <---- You've got fractions to work with here, so hang on.\r
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\n" ); document.write( "\n" ); document.write( "\"+5+=+D+-+%281%2F4%29D+-+%281%2F3%29D+\" <---- We just moved the fractional terms to the other side so they could be combined since they are like terms.\r
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\n" ); document.write( "\n" ); document.write( "The right side of the equation really is a task for you to compute \"+1+-+1%2F4+-+1%2F3+\". I trust that you know how to do that. That's actually equal to \"+12%2F12+-+3%2F12+-+4%2F12+\" which brings you to \"+5%2F12+\". The right side of your equation would then be \"+%285%2F12%29D+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+5+=+%285%2F12%29D+\" <---- the 1 - 1/4 - 1/3, then multiplied by D\r
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\n" ); document.write( "\n" ); document.write( "\"+5%2A%2812%2F5%29+=+D+\" <---- multiply both sides by the reciprocal of 5/12, which is 12/5\r
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\n" ); document.write( "\n" ); document.write( "\"+D+=+12+\" <---- the 5 in the numerator cancels with the 5 in the denominator. The trip was 12 miles total.
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