document.write( "Question 682567: A boeing 747 flies the 3000 mile distance from Los Angeles to NEw York, with the tailwind, in 5 hours. The return trip, against the wind, takes 6 hours. Find the speed of the plane and the speed of the wind. \n" ); document.write( "
Algebra.Com's Answer #423248 by mananth(16946)\"\" \"About 
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Find boat speed & current speed Both times given
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\n" ); document.write( "Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 6 hours
\n" ); document.write( "with wind 5 hours
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\n" ); document.write( "Distance against 3000 miles distance with wind 3000 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "3000 / ( x - y )= 6
\n" ); document.write( "6(x-y)=3000
\n" ); document.write( "6x-6y= 3000 ....................1
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\n" ); document.write( "3000/(x-y)= 5
\n" ); document.write( "5(x+y) =3000
\n" ); document.write( "5x+5y =3000 ...............2
\n" ); document.write( "Multiply (1) by 5
\n" ); document.write( "Multiply (2) by 6
\n" ); document.write( "we get y
\n" ); document.write( "30 x + -30 y = 15000
\n" ); document.write( "30 x + 30 = 18000
\n" ); document.write( "60 x = 33000
\n" ); document.write( "/ 60
\n" ); document.write( "x = 550 mph
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\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "6 x -6 y = 3000
\n" ); document.write( "3300 -6 -3300 = 3000
\n" ); document.write( "-6 y = 3000
\n" ); document.write( "-6 y = -300 mph
\n" ); document.write( " y = 50
\n" ); document.write( "Plane speed 550 mph
\n" ); document.write( "wind speed 50 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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