document.write( "Question 682555: solve f(x) = log3(x-2)
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Algebra.Com's Answer #423241 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
To graph this, use the well-known formula \"log%28b%2Cy%29=+%28ln+y%29%2F%28ln+b%29+\"\r
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\n" ); document.write( "\n" ); document.write( "In this case, \"f%28x%29+=+log+%283%2Cx-2%29+=+%28ln+%28x-2%29%29%2F%28ln+3%29+\". Are you allowed to use a graphing calculator? If so, it should look like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-1%2C10%2C-1%2C10%2C+ln%28x-2%29%2F1.1+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Unfortunately, using the algebra.com graphing system, I was not able to graph
\n" ); document.write( "\"y=+%28ln%28x-2%29%29%2F%28ln+3%29+\", so it was necessary to insert the approximate value of ln 3 = 1.1. I don't have any idea why, because my graphing calculator handles it just fine! I spent a lot of time trying to graph this using the algebra.com using the denominator of ln 3, but it just wouldn't do it for me.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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\n" ); document.write( "\n" ); document.write( "www.mathinlivingcolor.com.\r
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