document.write( "Question 681816: One number is 4 more than 3 times another. Their product is 20. \n" ); document.write( "
Algebra.Com's Answer #423239 by ReadingBoosters(3246)\"\" \"About 
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x = 3y+4
\n" ); document.write( "xy=20
\n" ); document.write( "...
\n" ); document.write( "(3y+4)y=20
\n" ); document.write( "\"3y%5E2+%2B+4y+-+20+=+0\"
\n" ); document.write( "...
\n" ); document.write( "(3y+10)(y-2)=0
\n" ); document.write( "3y+10=0
\n" ); document.write( "3y=-10
\n" ); document.write( "y = \"-10%2F3\" ==> does not work
\n" ); document.write( "y-2=0
\n" ); document.write( "\"highlight_green%28y=2%29\"
\n" ); document.write( "...
\n" ); document.write( "x = 3(2)+4=\"highlight_green%28x=10%29\"
\n" ); document.write( "...
\n" ); document.write( "The numbers are 10 and 2
\n" ); document.write( ".....................
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