document.write( "Question 61433This question is from textbook college algebra
\n" ); document.write( ": I need help with this one.\r
\n" ); document.write( "\n" ); document.write( "Jane and Terry went to Long Beach for a week. They needed to rent a car so they checked out two rental firms. Avis want $35 per day with no mileage fee. Downtown Toyota wanted $150 per week (7 days) and $.19 per mile. How many miles would they have to drive before the Toyota price is more than the Avis price?\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance for your help. \n" ); document.write( "

Algebra.Com's Answer #42323 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=the number of miles they would have to drive before the Toyota price is
\n" ); document.write( "more than the Avis price.\r
\n" ); document.write( "\n" ); document.write( "Assumption: They can only rent from Toyota by the week - not by the day.
\n" ); document.write( "Thus, Avis would cost $245 for the same amount of time (7 days).\r
\n" ); document.write( "\n" ); document.write( "Now we know that when the cost of Toyota per week (minimum rental) (150+.19x) equals the cost of Avis per week ($245), any additional mileage would make the Toyota price more than the Avis price. Thus, our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "(150+.19x)=245 and
\n" ); document.write( ".19x=245-150
\n" ); document.write( ".19x=95
\n" ); document.write( "x=500 miles \r
\n" ); document.write( "\n" ); document.write( "Hope this helps--------------ptaylor \n" ); document.write( "

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