document.write( "Question 682451: Please help. I need to solve this equation for t and I have no clue on how to do it. If you could please show the steps I would appreciate it very much.\r
\n" ); document.write( "\n" ); document.write( "(a)/(1+be^-kt)= (a/2)\r
\n" ); document.write( "\n" ); document.write( "This equation is asking for the time t at which the population size will be equal to half of its maximum (a/2). I need to solve for t.
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Algebra.Com's Answer #423212 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Please help. I need to solve this equation for t and I have no clue on how to do it. If you could please show the steps I would appreciate it very much.\r
\n" ); document.write( "\n" ); document.write( "(a)/(1+be^-kt)= (a/2)\r
\n" ); document.write( "\n" ); document.write( "This equation is asking for the time t at which the population size will be equal to half of its maximum (a/2). I need to solve for t.\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%29%2F%281+%2B+be%5E%28-kt%29%29+=+a%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%281+%2B+be%5E%28-kt%29%29+=+2a\" ----- Cross-multiplying\r
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\n" ); document.write( "\n" ); document.write( "\"1+%2B+be%5E%28-kt%29+=+2a%2Fa\"\r
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\n" ); document.write( "\n" ); document.write( "\"1+%2B+be%5E%28-kt%29+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "\"be%5E%28-kt%29+=+2+-+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"be%5E%28-kt%29+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28-kt%29+=+1%2Fb\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln+%281%2Fb%29+=+-+kt\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28ln%281%2Fb%29%2F%28-+k%29+=+t%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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