document.write( "Question 682426: Please show me how to rationalize the denominator for these questions:
\n" ); document.write( "a^2/square root of a\r
\n" ); document.write( "\n" ); document.write( "Square root of a^2/square root of 2\r
\n" ); document.write( "\n" ); document.write( "3square root of n^2/square root of 5\r
\n" ); document.write( "\n" ); document.write( "Square root of x^2/Square root of 3\r
\n" ); document.write( "\n" ); document.write( "-x^2/square root of y\r
\n" ); document.write( "\n" ); document.write( "3x/square root of 5
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Algebra.Com's Answer #423192 by lynnlo(4176)\"\" \"About 
You can put this solution on YOUR website!
I AM GIVING YOU AN EXAMPLE SO YOU CAN STUDY AND UNDERSTAND IT BETTER
\n" ); document.write( " RATIONALIZE
\n" ); document.write( " 3/2+√5
\n" ); document.write( "STEP (1)SIMPLIFY THE SQUARE ROOT IN THE DENOMINATOR
\n" ); document.write( "√5 IS ALREADY SIMPLIFIED,DO NOTHING HERE
\n" ); document.write( "STEP (2) MULTIPLY THE NUM.& DENO.BY THE DENOMINATORS CONJUGATE*2-√5
\n" ); document.write( "3/2+√5 times 2-√5/2-√5=3(2-√5)/(2+√5)(2-√5)=6-3√5)/4+2√5-2√5)+5=6-3√5/9
\n" ); document.write( "STEP(3) SIMPLIFY
\n" ); document.write( "6-3√5/9=2-√5/3
\n" ); document.write( "6-3√5 OVER 9=2-√5OVER 3
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