document.write( "Question 682221: Hello I have to solve three equations with three variables
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document.write( "The equations are
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document.write( "6q-r+2s=8
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document.write( "2q+3r-s=-9
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document.write( "4q+2r+5s=1
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document.write( "I have the equations using the process of elimination to find x y and z
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document.write( "The problem is I've been on this question for more than an hour either getting decimals as my answers and or equations which I can't solve
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document.write( "Honestly I don't know what I'm doing wrong.Ive tried to eliminate the q's first but afterwards towards solving I got 2.5 which I know is wrong \n" );
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Algebra.Com's Answer #423148 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 6q - r + 2s = 8 \n" ); document.write( "2q + 3r - s = -9 \n" ); document.write( "4q + 2r + 5s= 1 \n" ); document.write( ": \n" ); document.write( "There are several ways to do this, sometimes it's helpful to slip \"substitution\" among the eliminations. \n" ); document.write( ": \n" ); document.write( "Multiply 1st eq by -1 and add to the other 2 \n" ); document.write( "-6q + r - 2s = -8 \n" ); document.write( "2q + 3r - s = -9 \n" ); document.write( "4q + 2r + 5s = 1 \n" ); document.write( "-------------------Adding eliminates q \n" ); document.write( "6r + 2s = -16 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "3r + s = -8 \n" ); document.write( "s = -3r - 8 \n" ); document.write( ": \n" ); document.write( "Taking the last two equations, multiply the middle equation by 2 \n" ); document.write( "4q + 6r - 2s = -18 \n" ); document.write( "4q + 2r + 5s = 1 \n" ); document.write( "---------------------Subtraction eliminates q \n" ); document.write( "4r - 7s = -19 \n" ); document.write( "replace s with (-3r-8) \n" ); document.write( "4r -7(-3r-8) = -19 \n" ); document.write( "4r + 21r + 56 = -19 \n" ); document.write( "25r = -19 - 56 \n" ); document.write( "25r = -75 \n" ); document.write( "r = -75/25 \n" ); document.write( "r = -3 \n" ); document.write( ": \n" ); document.write( "Find s \n" ); document.write( "s = -3(-3) - 8 \n" ); document.write( "s = 9 - 8 \n" ); document.write( "s = 1 \n" ); document.write( ": \n" ); document.write( "Find q using the first equation \n" ); document.write( "6q -r + 2s = 8, \n" ); document.write( "replace r and s \n" ); document.write( "6q -(-3) + 2(1) = 8 \n" ); document.write( "6q + 3 + 2 = 8 \n" ); document.write( "6q = 8 - 5 \n" ); document.write( "6q = 3 \n" ); document.write( "q = 3/6 \n" ); document.write( "q = .5 or 1/2 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can confirm this in the original equations \n" ); document.write( " |