document.write( "Question 61416: well i`ve been trying this problem for hours \"A field has a perimeter of 240 yards. The length is 20 yards less than the width. Find the length and width\"?\r
\n" ); document.write( "\n" ); document.write( " I cant find the answer.
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Algebra.Com's Answer #42313 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
1240=2*W+2(W-20)
\n" ); document.write( "240=2W+2W-40
\n" ); document.write( "4W=240+40
\n" ); document.write( "4W=280
\n" ); document.write( "W=280/4
\n" ); document.write( "W=70 YARDS WIDE THEN THE LENGTH IS
\n" ); document.write( "70-20=50 YARDS FOR THE LENGTH
\n" ); document.write( "PROOF
\n" ); document.write( "240=2*70+2*50
\n" ); document.write( "240=140+100
\n" ); document.write( "240=240
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