document.write( "Question 61442This question is from textbook Calculus for the Managerial, Life, and Social Sciences
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document.write( ": A rectangular box is to have a square base and a volume of 20 feet cubed. If the material for the base costs $.30/square foot, the material for the sides costs $.10/square foot, and the material for the top costs $.20/square foot, determine the dimensions of the box that can be constructed at minimun cost. \n" );
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Algebra.Com's Answer #42311 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangular box is to have a square base and a volume of 20 feet cubed. If the material for the base costs $.30/square foot, the material for the sides costs $.10/square foot, and the material for the top costs $.20/square foot, determine the dimensions of the box that can be constructed at minimum cost \n" ); document.write( ": \n" ); document.write( "Let y = the cost of the box \n" ); document.write( ": \n" ); document.write( "Let x = one side of the square base \n" ); document.write( ": \n" ); document.write( "Let h = height of the box \n" ); document.write( ": \n" ); document.write( "We know that the box has to be 20 cu ft: \n" ); document.write( "x^2*h = 20 \n" ); document.write( "h = (20/x^2) \n" ); document.write( ": \n" ); document.write( "Costs: \n" ); document.write( "Base = .30(x^2) \n" ); document.write( "Top = .20(x^2) \n" ); document.write( "1 side = .10(x*(20/x^2)) = .10(20/x) \n" ); document.write( "4 sides = .40(20/x) = 8/x \n" ); document.write( ": \n" ); document.write( "Total cost: \n" ); document.write( "y = Base + Top + 4 sides \n" ); document.write( "y =.30(x^2) + .20(x^2) + 8/x \n" ); document.write( "y = .5x^2 + 8/x \n" ); document.write( "Graph it: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Looks like min cost (y) occurs when x = 2 ft, looks like a cost(y) of $6.00 \n" ); document.write( ": \n" ); document.write( "Then the height = 20/2^2 = 5 ft \n" ); document.write( ": \n" ); document.write( "What is the cost then? \n" ); document.write( "top .30(2^2) = 1.20 \n" ); document.write( "bot .20(2^2) = 0.80 \n" ); document.write( "hth .10(2*5) = 1.00 * 4 sides = $4.00 \n" ); document.write( "Total cost = $6.00 like the graph indicates. \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Check: 2 * 2 * 5 = 20 cu ft as required\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |