document.write( "Question 682141: in triangle ABC, the altitudes to the side AB and AC are congruent. Prove that quadrilateral PBCQ is:
\n" ); document.write( "a. trapezoid
\n" ); document.write( "b. isosceles trapezoid
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Solution :\r
\n" ); document.write( "\n" ); document.write( "In triangle ABC, Altitude from B and C are equal with each other. hence we have:
\n" ); document.write( "BQ = PC \r
\n" ); document.write( "\n" ); document.write( "now consider two triangle PBC and Triangle QCB
\n" ); document.write( " we have \n" ); document.write( "BC = CB is the common sides.
\n" ); document.write( "BQ = PC given equal altitudes.\r
\n" ); document.write( "\n" ); document.write( "Hence by RHS rule ,
\n" ); document.write( "Triangle PBC is congruent to Triangle QCB.
\n" ); document.write( "PB = QC by ( CPCT )\r
\n" ); document.write( "\n" ); document.write( "also these two triangles are congruent then there height must be equal , hence we
\n" ); document.write( "can say that they must lie between the parallel lines ( PQ and BC )
\n" ); document.write( "hence PBQC is the ISOSCELES Trapezoid ( since PQ parallel BC and PB = QC )
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