document.write( "Question 682141: in triangle ABC, the altitudes to the side AB and AC are congruent. Prove that quadrilateral PBCQ is:
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document.write( "a. trapezoid
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document.write( "b. isosceles trapezoid \n" );
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Algebra.Com's Answer #423071 by vidya p(12)![]() ![]() ![]() You can put this solution on YOUR website! Solution :\r \n" ); document.write( "\n" ); document.write( "In triangle ABC, Altitude from B and C are equal with each other. hence we have: \n" ); document.write( "BQ = PC \r \n" ); document.write( "\n" ); document.write( "now consider two triangle PBC and Triangle QCB \n" ); document.write( " we have \n" ); document.write( "BQ = PC given equal altitudes.\r \n" ); document.write( "\n" ); document.write( "Hence by RHS rule , \n" ); document.write( "Triangle PBC is congruent to Triangle QCB. \n" ); document.write( "PB = QC by ( CPCT )\r \n" ); document.write( "\n" ); document.write( "also these two triangles are congruent then there height must be equal , hence we \n" ); document.write( "can say that they must lie between the parallel lines ( PQ and BC ) \n" ); document.write( "hence PBQC is the ISOSCELES Trapezoid ( since PQ parallel BC and PB = QC ) |