document.write( "Question 682162: A labourer is engaged for 20 days on the condition that he will receive Rs.80 for each day he works and will be fined Rs.6 for each day he is absent. If he receive Rs.826 in all, how many days did he remain absent.? \n" ); document.write( "
Algebra.Com's Answer #423070 by vidya p(12)\"\" \"About 
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This question is related to simultaneous linear equations in two variables.\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "Let x be the number of working days
\n" ); document.write( "and y be the number of absent days.\r
\n" ); document.write( "\n" ); document.write( "since total number of days are 20 ,
\n" ); document.write( "hence we get: x + y = 20 \r
\n" ); document.write( "\n" ); document.write( "now second condition says
\n" ); document.write( "cost for working days is $80 , hence total cost is 80x \r
\n" ); document.write( "\n" ); document.write( "cost reduced for absent days is $ 6 ,
\n" ); document.write( "hence total cost reduced is 6y \r
\n" ); document.write( "\n" ); document.write( "now total amount obtained is $ 826
\n" ); document.write( "therefore the equation is: 80x - 6y = 826 \r
\n" ); document.write( "\n" ); document.write( "now we can solve by elimination method:
\n" ); document.write( " x + y = 20 multiply by 6
\n" ); document.write( "we get 6x + 6y = 120
\n" ); document.write( "and 80x -6y = 826
\n" ); document.write( "now add both the equation we get :\r
\n" ); document.write( "\n" ); document.write( "86x = 946 \r
\n" ); document.write( "\n" ); document.write( "x = 946/86
\n" ); document.write( "x = 11\r
\n" ); document.write( "\n" ); document.write( "plug x = 11 in first equation and get y?
\n" ); document.write( "x + y = 20
\n" ); document.write( "11 + y = 20
\n" ); document.write( "y = 9 \r
\n" ); document.write( "\n" ); document.write( "hence 11 are working days
\n" ); document.write( "and so he remain absent for 9 days.
\n" ); document.write( "
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