document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=682150>Question 682150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x^2+3y^2-6y+12x=24 circle, ellipse, or hyperbola<BR>\n" );
document.write( "(3x^2+12x)+(3y^2-6y)=24<BR>\n" );
document.write( "3(x^2+4x+4)+3(y^2-2y+1)=24+12+3<BR>\n" );
document.write( "                                         </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423068 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^2+3y^2-6y+12x=24 circle, ellipse, or hyperbola<BR>\n" );
document.write( "(3x^2+12x)+(3y^2-6y)=24<BR>\n" );
document.write( "3(x^2+4x+4)+3(y^2-2y+1)=24+12+3<BR>\n" );
document.write( "3(x+2)^2+ 3(y-1)^2 = 39<BR>\n" );
document.write( "(x+2)^2 + (y-2)^2 = 13<BR>\n" );
document.write( "====<BR>\n" );
document.write( "Circle with center at (-2,2) and radius = sqrt(13)<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );