document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=682079>Question 682079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is my problem as written in my homework:<BR>\n" );
document.write( "A metallurgist needs to produce 10kg of an alloy which is 65% copper and 35% tin. He has an alloy which is 50% copper and 50% tin. How much of this 50-50 alloy must he melt together with pure copper to make the desired alloy? How much pure copper must he use?\r<BR>\n" );
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document.write( "Here is how I attempted to solve the problem:<BR>\n" );
document.write( "(10-x)(.50)(.50)+(x)(1)=10(.65)(.35)\r<BR>\n" );
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document.write( "So the answer that I got was that he would need 2.03 kg of the pure copper and 7.97 kilograms of the 50-50 mixture.\r<BR>\n" );
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document.write( "When I substituted the numbers into my equation, it did not come out right.\r<BR>\n" );
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document.write( "Thank you for your time and patience. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423038 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here is my problem as written in my homework:<BR>\n" );
document.write( "A metallurgist needs to produce 10kg of an alloy which is 65% copper and 35% tin. He has an alloy which is 50% copper and 50% tin. How much of this 50-50 alloy must he melt together with pure copper to make the desired alloy? How much pure copper must he use? <BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=amt of pure copper to be melted with 50-50 alloy<BR>\n" );
document.write( "10-x=amt of 50-50 alloy to be melted with pure copper<BR>\n" );
document.write( "..<BR>\n" );
document.write( "100%*x+50%*(10-x)=65%*10<BR>\n" );
document.write( "x+(10-x)/2=6.5<BR>\n" );
document.write( "2x+10-x=2*6.5=13<BR>\n" );
document.write( "x+10=13<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "10-x=7<BR>\n" );
document.write( "amt of pure copper to be melted with 50-50 alloy=3kg<BR>\n" );
document.write( "amt of 50-50 alloy to be melted with pure copper=7kg </SPAN>\n" );
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