document.write( "Question 682040: a rowing team rowing with the current, traveled 40km in 2 hrs. rowing against the current the team can only travel 16 km in 2 hrs find the team rowing rate in calm water and the rate of the current \n" ); document.write( "

Algebra.Com's Answer #422997 by mananth(16946) $\"\"$ $\"About$

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Rowing speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 2 hours
\n" ); document.write( "with current 2 hours
\n" ); document.write( "
\n" ); document.write( "Distance with current 40 miles distance against current 16
\n" ); document.write( "t=d/r against current (x-y)
\n" ); document.write( "16.00 / ( x - y )= 2.00
\n" ); document.write( "
\n" ); document.write( "2.00 x - -2.00 y = 16.00 ....................1
\n" ); document.write( "with current (x+y)
\n" ); document.write( "40.00 / ( x + y )= 2.00
\n" ); document.write( "2.00 ( x + y ) = 40.00
\n" ); document.write( "2.00 x + 2.00 y = 40.00 ...............2
\n" ); document.write( "Multiply (1) by 1.00
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "we get y
\n" ); document.write( "2.00 x + -2.00 y = 16.00
\n" ); document.write( "2.00 x + 2.00 = 40.00
\n" ); document.write( "4.00 x = 56.00
\n" ); document.write( "/ 4.00
\n" ); document.write( "x = 14 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "2 x -2 y = 16
\n" ); document.write( "28 -2 -28 = 16
\n" ); document.write( "-2 y = 16
\n" ); document.write( "-2 y = -12 mph
\n" ); document.write( " y = 6
\n" ); document.write( "Rowing 14 mph
\n" ); document.write( "current 6 mph
\n" ); document.write( " \n" ); document.write( "

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