document.write( "Question 681907: The total of three numbers is 118. The second one is seventeen less that the first one;the third one is five more than three times the first one. Form an equation and solve it to find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #422956 by tsewaitung(11)![]() ![]() ![]() You can put this solution on YOUR website! let the first number be x,the second number be y, and the third number be z. \n" ); document.write( "from the question, we have \n" ); document.write( "x+y+z=118 \n" ); document.write( "y=x-17 \n" ); document.write( "z=3x+5 \n" ); document.write( "by substituting the second and the third equation into the first equation, we have \n" ); document.write( "x+(x-17)+(3x+5)=118 \n" ); document.write( " x+x-17+3x+5=118 \n" ); document.write( " 5x-12=118 \n" ); document.write( " 5x=130 \n" ); document.write( " \n" ); document.write( "by substituting x=26 into the second equation, we have \n" ); document.write( " y=(26)-17 \n" ); document.write( " \n" ); document.write( "by substituting x=26 into the third equation, we have \n" ); document.write( " z=3(26)+5 \n" ); document.write( " z=78+5 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "checking: \n" ); document.write( "by substituting x=26, y=9, and z=83 into the first equation, we have \n" ); document.write( "(26)+(9)+(83) \n" ); document.write( "=118\r \n" ); document.write( "\n" ); document.write( "the three numbers are 26,9,and 83. \n" ); document.write( " |