document.write( "Question 681977: Graph the following point-slope form equations.
\n" ); document.write( "1. y-3=2(x-1)
\n" ); document.write( "2. y-5=(-1/4)x+2
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Algebra.Com's Answer #422944 by ReadingBoosters(3246)\"\" \"About 
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Transform the point-slope form to slope intercept for
\n" ); document.write( "y-3=2(x-1)
\n" ); document.write( "y-3=2x-2
\n" ); document.write( "y =2x-2+3
\n" ); document.write( "y=2x + 1
\n" ); document.write( "y intercept is 1, plot (0,1)
\n" ); document.write( "...
\n" ); document.write( "x intercept is where y = 0
\n" ); document.write( "0=2x+1
\n" ); document.write( "-1 = 2x
\n" ); document.write( "x = \"-1%2F2\", plot (\"-1%2F2\",0)
\n" ); document.write( "...
\n" ); document.write( "From the point slope plot the point (1,3)
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\n" ); document.write( "Draw a line through the point and the intercept
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\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2x%2B1%29\"
\n" ); document.write( "...
\n" ); document.write( "y-5=(-1/4)x+2
\n" ); document.write( "y = (-1/4)x+2+5
\n" ); document.write( "y = (-1/4)x + 7
\n" ); document.write( "y intercept is 7, plot (0,7)
\n" ); document.write( "x intercept is where y = 0
\n" ); document.write( "0 = (-1/4)x + 7
\n" ); document.write( "-7 = (-1/4)x
\n" ); document.write( "28 = x, plot (28,0)
\n" ); document.write( "...
\n" ); document.write( "Taking y-5 = (-1/4)x+2 backward into point-slope
\n" ); document.write( "y-5 = (-1/4)(x + -8)
\n" ); document.write( "Plot the intercepts and the point (8,5) and draw a line through them.
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\n" ); document.write( "\"graph%28300%2C200%2C-10%2C30%2C-10%2C10%2C%28-1%2F4%29x%2B7%29\"
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