document.write( "Question 681996: Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( "^3 \"sqrt+3x-2\"= -5\r
\n" ); document.write( "\n" ); document.write( "This is what I have gotten but not sure if it is correct:
\n" ); document.write( "3x-2=-5^3
\n" ); document.write( "3x-2=-75
\n" ); document.write( "3x=-73
\n" ); document.write( "x=-73/3\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #422937 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
-5^3 is NOT -75 it is \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-5^3 = -(5^3) = -(5*5*5) = -125, so it should be\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3x-2=-5^3
\n" ); document.write( "3x-2=-125
\n" ); document.write( "3x=-123
\n" ); document.write( "x=-123/3
\n" ); document.write( "x = -41\r
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