document.write( "Question 681993: it says,\"Sketch the graphs using the roots to find the function and the turning point.\" \r
\n" ); document.write( "\n" ); document.write( "x=-8, x=4\r
\n" ); document.write( "\n" ); document.write( "x=-3, x=3
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Algebra.Com's Answer #422935 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
Given the roots of -8 and 4; Plot (-8,0) and (4,0)
\n" ); document.write( "(x+8) and (x-4) = 0
\n" ); document.write( "(x+8)(x-4)=0
\n" ); document.write( "\"x%5E2-4x+%2B+8x+-+32\"=0
\n" ); document.write( "f(x) = \"x%5E2+%2B+4x+-+32\"
\n" ); document.write( "...
\n" ); document.write( "complete the square to find the turning point
\n" ); document.write( "\"x%5E2+%2B+4x+=+32\"
\n" ); document.write( "\"x%5E2+%2B+4x+%2B+4+=+32+%2B+4\"
\n" ); document.write( "(x+2)^2 = 36
\n" ); document.write( "y = (x+2)^2 - 36
\n" ); document.write( "vertex/turning point of (-2,-36)
\n" ); document.write( "...
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-40%2C20%2Cx%5E2%2B4x-32%29\"
\n" ); document.write( "...
\n" ); document.write( "Using roots of -3 and 3; Plot (-3,0) and (3, 0)
\n" ); document.write( "(x+3) and (x-3)
\n" ); document.write( "(x+3)(x-3)=0
\n" ); document.write( "\"x%5E2%2B3x-3x-9\"=0
\n" ); document.write( "f(x) = \"x%5E2-9\"
\n" ); document.write( "...
\n" ); document.write( "turning point (0,-9)
\n" ); document.write( "...
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-15%2C10%2Cx%5E2-9%29\"
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