document.write( "Question 681992: it says, \"Sketch the graphs, using the function and three points: two roots and the turning point.\r
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document.write( "f(x)= x^2-2x-8\r
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document.write( "f(x)= x^2-2x-15 \n" );
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Algebra.Com's Answer #422933 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! f(x) = \n" ); document.write( "=(x-4)(x+2) \n" ); document.write( "roots/zeros/intercepts at 4 and -2 \n" ); document.write( "Plot (4, 0) and (-2, 0) \n" ); document.write( "... \n" ); document.write( "complete the square to find turning point \n" ); document.write( "x^2 - 2x - 8 = 0 \n" ); document.write( "x^2 - 2x + 1 = 8 + 1 \n" ); document.write( "x^2 - 2x + 1 = 9 \n" ); document.write( "y = (x-1)^2 - 9 \n" ); document.write( "vertex/turning point at 1, -9 \n" ); document.write( "Plot (1,-9) \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "f(x) = \n" ); document.write( "= (x-5)(x+3) \n" ); document.write( "roots/zeros/intercepts at 5 and -3 \n" ); document.write( "Plot (5, 0) and (-3, 0) \n" ); document.write( "... \n" ); document.write( "complete the square to find the turning point \n" ); document.write( "x^2 - 2x - 15 = 0 \n" ); document.write( "x^2 - 2x = 15 \n" ); document.write( "x^2 - 2x + 1 = 15 + 1 \n" ); document.write( "(x-1)^2 - 16 = 0 \n" ); document.write( "y = (x-1)^2 - 16 \n" ); document.write( "Plot (1,-16) \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "..................... \n" ); document.write( "Have more questions? \n" ); document.write( "Email: HomeworkHelpers@readingboosters.com \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Website: www.MyHomeworkAnswers.com \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( " |