document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61434>Question 61434</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0030700396/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Peggy has a 500 milliliters of a 60% solution of copper sulfate.  How many milliliters of a 30% solution of copper sulfate should be added to obtain a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42291 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 500*.6+.3x=(500+x).5<BR>\n" );
document.write( "300+.3x=250+.5x<BR>\n" );
document.write( ".3x-.5x=250-300<BR>\n" );
document.write( "-.2x=-50<BR>\n" );
document.write( "x=-50/-.2<BR>\n" );
document.write( "x=250 ml of 30% copper sulfate is needed<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "500*.6+.3*250=(500+250).5<BR>\n" );
document.write( "300+75=750*.5<BR>\n" );
document.write( "375=375 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );