document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=681848>Question 681848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two stations A and B on a railway line are 144 kilometers apart. A fast train starts from B at 9 a.m., another fast train travelling at the same speed starts from A at 10 a.m. A slow train starts from B at 10:20 a.m., the fast train A meets the other fast train at 11:30 a.m., and the slow train at 12:32 p.m. When does the slow train reach A?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422826 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ans :<BR>\n" );
document.write( "Two stations A and B on a railway line are 144 kilometers apart<BR>\n" );
document.write( "both the fast trains travel at same speed say s km/hr towards each other <BR>\n" );
document.write( "& met at 11:30 a.m i.e after 2hrs 30 mins =2.5 hr<BR>\n" );
document.write( "so the distance travelled in 2.5hrs by both trains =2.5*2*skm=5s km (as travelling towards each other)<BR>\n" );
document.write( "so obviously 5s=144 km (as both are meeting)<BR>\n" );
document.write( "so s=144/5 km/hr=28.8 km/hr<BR>\n" );
document.write( "now let us consider the slow train which meets the fast train at 12.32 pm i.e.after 2hrs & 32 mins=2+32/60 hr=2.53 hrs<BR>\n" );
document.write( "the distance travelled by fast train in 2.53hrs=28.8*2.53=72.96=73 km (approx)<BR>\n" );
document.write( "so the dist travelled by the slow train=144-73=71 kms <BR>\n" );
document.write( "this distance was travelled by the slow train in 12.32-10.20=2hrs 12min=2.2 hrs<BR>\n" );
document.write( "now the speed of the slow train=71/2.2=32.27 km/hr<BR>\n" );
document.write( "so thetime taken by the slow train to travel 144 kms=144/32.27=4.46hrs<BR>\n" );
document.write( "=4hrs 27.7min =4hrs & 28 mins (approx)<BR>\n" );
document.write( "so the time of reaching of the slow train=10.20+4hrs 27min=14hrs & 47min<BR>\n" );
document.write( "=2.47pm<BR>\n" );
document.write( "ans\r<BR>\n" );
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