document.write( "Question 681141: What is the vertex and the axis of symmetry of the parabola y=x^2+5x-6 \n" ); document.write( "
Algebra.Com's Answer #422821 by lwsshak3(11628)\"\" \"About 
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What is the vertex and the axis of symmetry of the parabola
\n" ); document.write( "y=x^2+5x-6
\n" ); document.write( "complete the square:
\n" ); document.write( "y=(x^2+5x+25/4)-6-25/4
\n" ); document.write( "y=(x+5/2)^2-24/4-25/4
\n" ); document.write( "y=(x+5/2)^2-49/4
\n" ); document.write( "This is an equation of a parabola that opens upwards.
\n" ); document.write( "Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex
\n" ); document.write( "For given equation: y=(x+5/2)^2-49/4
\n" ); document.write( "vertex: (-5/2,-49/4)
\n" ); document.write( "axis of symmetry: x=-5/2
\n" ); document.write( "see graph below:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-20%2C+10%2C%28x%2B5%2F2%29%5E2-49%2F4%29+\"
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