document.write( "Question 681797: A motor boat leaves the harbor traveling at 10 mph. Three hours later a cabin cruiser leaves the harbor traveling at 30 mph. In how many hours after the cabin cruiser leaves will it be along side the motor boat? \n" ); document.write( "
Algebra.Com's Answer #422810 by stanbon(75887)\"\" \"About 
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A motor boat leaves the harbor traveling at 10 mph. Three hours later a cabin cruiser leaves the harbor traveling at 30 mph. In how many hours after the cabin cruiser leaves will it be along side the motor boat?
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\n" ); document.write( "Motor Boat DATA:
\n" ); document.write( "rate = 10 mph ; time = x + 3 hrs ; distance = 10(x+3) miles
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\n" ); document.write( "Cruiser DATA:
\n" ); document.write( "rate = 30 mph ; time = x hrs ; distance = 30x miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "10x + 30 = 30x
\n" ); document.write( "20x = 30
\n" ); document.write( "x = 3/2 hrs. (time to catch the motor boat)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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