document.write( "Question 681797: A motor boat leaves the harbor traveling at 10 mph. Three hours later a cabin cruiser leaves the harbor traveling at 30 mph. In how many hours after the cabin cruiser leaves will it be along side the motor boat? \n" ); document.write( "
Algebra.Com's Answer #422810 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A motor boat leaves the harbor traveling at 10 mph. Three hours later a cabin cruiser leaves the harbor traveling at 30 mph. In how many hours after the cabin cruiser leaves will it be along side the motor boat? \n" ); document.write( "----- \n" ); document.write( "Motor Boat DATA: \n" ); document.write( "rate = 10 mph ; time = x + 3 hrs ; distance = 10(x+3) miles \n" ); document.write( "------- \n" ); document.write( "Cruiser DATA: \n" ); document.write( "rate = 30 mph ; time = x hrs ; distance = 30x miles \n" ); document.write( "--------------------------- \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "10x + 30 = 30x \n" ); document.write( "20x = 30 \n" ); document.write( "x = 3/2 hrs. (time to catch the motor boat) \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |