document.write( "Question 681777: If an object is projected vertically upward from an altitude of a feet with an initial velocity of v ft/sec, then its distance s(t) above the ground after t seconds is
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document.write( "s(t) = −16t2 + vt + a.
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document.write( "If s(1) = 99 and s(4) = 129, what are v and a? \n" );
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Algebra.Com's Answer #422783 by mananth(16946)![]() ![]() You can put this solution on YOUR website! s(t) = −16t2 + vt + a. \n" ); document.write( "If s(1) = 99 and s(4) = 129, what are v and a? \r \n" ); document.write( "\n" ); document.write( "99= -16(1)^2+v(1)+a \n" ); document.write( "99=v+a-16 \n" ); document.write( "v+a=99+16 \n" ); document.write( "v+a=115..........(1)\r \n" ); document.write( "\n" ); document.write( "129= -16(4^2)+4v+a\r \n" ); document.write( "\n" ); document.write( "129=-256+4v+a\r \n" ); document.write( "\n" ); document.write( "4v+a=129+256 \n" ); document.write( "4v+a=386...........(2)\r \n" ); document.write( "\n" ); document.write( "Solve (1) & (2) \r \n" ); document.write( "\n" ); document.write( "subtract (2) from (1) \n" ); document.write( "-3v=-276 \n" ); document.write( "v=92 \n" ); document.write( "Plug v in equation above to get a \n" ); document.write( " |