document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=681759>Question 681759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A silversmith has two alloys, one containing 60% silver and the other 40% silver. How much of each should be melted and combined to obtain 800 grams of an alloy containing 54% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422774 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	Silver percent	----------------			quantity									<BR>\n" );
document.write( "Metal alloy I	60	----------------			x	grams								<BR>\n" );
document.write( "Metal alloy II	40	------	800	-	x	grams								<BR>\n" );
document.write( "Mixture	54	----------------	800											<BR>\n" );
document.write( "														<BR>\n" );
document.write( "60x+	40(800	-x)=54	*	800		<BR>\n" );
document.write( "6000x	+4000(800-x)	=	4320000				<BR>\n" );
document.write( "6000x+	3200000	-4000x	=	4320000				<BR>\n" );
document.write( "6000x-	4000x=	4320000	-	-3200000				<BR>\n" );
document.write( "2000	x			=	1120000									<BR>\n" );
document.write( "/	2000													<BR>\n" );
document.write( "	x			=	560		grams			60.00%		Metal alloy I		<BR>\n" );
document.write( "					240		grams			40.00%		Metal alloy II		<BR>\n" );
document.write( "														<BR>\n" );
document.write( "m.ananth@hotmail.ca														<BR>\n" );
document.write( "	 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );