document.write( "Question 681695: The length of a rectangle is 6 inches less than twice the width. If the perimeter of the rectangle is 90 inches, what are its dimensions? \n" ); document.write( "

Algebra.Com's Answer #422770 by ReadingBoosters(3246) $\"\"$ $\"About$

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Given
\n" ); document.write( "l = 2w-6
\n" ); document.write( "p = 90
\n" ); document.write( "...
\n" ); document.write( "Knowing
\n" ); document.write( "p = 2l + 2w
\n" ); document.write( "...
\n" ); document.write( "90 = 2(2w-6) + 2w
\n" ); document.write( "Distribute the 2
\n" ); document.write( "90 = 4w - 12 + 2w
\n" ); document.write( "Combine like terms
\n" ); document.write( "90 = 6w - 12
\n" ); document.write( "90 + 12 = 6w
\n" ); document.write( "102 = 6w
\n" ); document.write( "Divide both sides by 6
\n" ); document.write( " $\"highlight_green%28w+=+17%29\"$
\n" ); document.write( "l = 2(17)-6 = 34-6 = $\"highlight_green%28l=28%29\"$ \r
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