document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=681673>Question 681673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 log base 5 x + 3 log base 5 (x-2).  My instructor said the answer is <BR>\n" );
document.write( "log 32.5/log square root of 2.  I understand where he got the log square root of 2 but don't understand the log 32.5.  I wasn't sure if I wrote his review problem down correctly.<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422738 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 log base 5 x + 3 log base 5 (x-2)<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2log%285%2Cx%29+%2B+3log%285%2C%28x-2%29%29 ALIGN=MIDDLE  ALT=\"2log%285%2Cx%29+%2B+3log%285%2C%28x-2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= log(x^2) + log(x-2)^3)<BR>\n" );
document.write( "= log(x^2*(x-2)^3}}}<BR>\n" );
document.write( "All logs base 5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );