document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=681575>Question 681575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> m(3,-3) is the midpoint of RS. If S has coordinates (8,2) fine the coordinates of R </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422707 by </B><A HREF=/tutors/aboutme.mpl?userid=Jolliano><B>Jolliano(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jolliano><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jolliano><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the coordinates of R be (x1,y1). <BR>\n" );
document.write( "Then, ([8 + x1]/2,[2 + y1]) = (3,-3)<BR>\n" );
document.write( "Taking it one at a time,<BR>\n" );
document.write( "(8 + x1)/2 = 3<BR>\n" );
document.write( "Cross multiplying,<BR>\n" );
document.write( "8 + x1= 3 * 2 <BR>\n" );
document.write( "x1 = 6 - 8<BR>\n" );
document.write( "x1 = -2.<BR>\n" );
document.write( "Also,<BR>\n" );
document.write( "(2 + y1)/2 = -3<BR>\n" );
document.write( "2 + y1 = 2 * -3<BR>\n" );
document.write( "y1 = -6 - 2<BR>\n" );
document.write( "y1 = -8.<BR>\n" );
document.write( "Coordinates of R are (-2,-8). </SPAN>\n" );
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