document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=681513>Question 681513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find all values x over the interval (0, 2pi), for the equation y=sqrt(3)tan(x)=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422700 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find all values x over the interval (0, 2pi), <BR>\n" );
document.write( "for the equation sqrt(3)tan(x)=1\r<BR>\n" );
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document.write( "-----<BR>\n" );
document.write( "tan(x) = 1/sqrt(3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Draw a 30-60-90 right triangle.<BR>\n" );
document.write( "Let the side opposite the 30 degree angle be \"1\".<BR>\n" );
document.write( "Then hypotenuse = 2<BR>\n" );
document.write( "And base = sqrt(3)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Notice that tan(30) = 1/sqrt(3)<BR>\n" );
document.write( "So pi/6 is one of your answers.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "The corresponding angle in QIII is 210 degrees or (7/6)pi<BR>\n" );
document.write( "that is your other angle solution.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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