document.write( "Question 681582: if cos of beta = 2/3 what is the tan of beta? \n" ); document.write( "
Algebra.Com's Answer #422696 by stanbon(75887)\"\" \"About 
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if cos of beta = 2/3 what is the tan of beta?
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\n" ); document.write( "cos = x/r, so if cos = 2/3, x = 2 and r = 3
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\n" ); document.write( "Solve for \"y\":
\n" ); document.write( "y^2 = r^2-x^2
\n" ); document.write( "y = sqrt[3^2-2^2] = sqrt(5)
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\n" ); document.write( "Now you know x,y, and r so you can calculate ALL of the trig
\n" ); document.write( "functions for the angle beta.
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\n" ); document.write( "tan = y/x = sqrt(5)/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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