document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=681544>Question 681544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -2(r+3s)+5(-r-s) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422684 by </B><A HREF=/tutors/aboutme.mpl?userid=skue><B>skue(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=skue><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  This solution holds true if u are asked to perform the operation.<BR>\n" );
document.write( "Perform the distributive property of addition to the equation.\r<BR>\n" );
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document.write( "-2(r+3s)+ 5(-r-s)\r<BR>\n" );
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document.write( "-4r - 6s + (-5r-5s)\r<BR>\n" );
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document.write( "-4r - 6s - 5r -5s \r<BR>\n" );
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document.write( "-7r - 11s<BR>\n" );
document.write( " You could equate it to zero, </SPAN>\n" );
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