document.write( "Question 681470: Determine which, if any, of the three statements are equivalent. Give a reason for your conclusion. Show complete work and submit your solution to the Dropbox. \r
\n" ); document.write( "\n" ); document.write( "I) If the cat does not have claws, then the cat cannot scratch the furniture.
\n" ); document.write( "II) If the cat can scratch the furniture, then the cat has claws.
\n" ); document.write( "III) If the cat has claws, then the cat can scratch the furniture.
\n" ); document.write( "a. I and II are equivalent
\n" ); document.write( "b. I and III are equivalent
\n" ); document.write( "c. II and III are equivalent
\n" ); document.write( "d. I, II, and III are equivalent
\n" ); document.write( "e. None are equivalent \r
\n" ); document.write( "\n" ); document.write( "(Points : 4)
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Algebra.Com's Answer #422672 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
the statements are:
\n" ); document.write( "I) If the cat does not have claws, then the cat cannot scratch the furniture.
\n" ); document.write( "II) If the cat can scratch the furniture, then the cat has claws.
\n" ); document.write( "III) If the cat has claws, then the cat can scratch the furniture.
\n" ); document.write( "you can solve this using truth tables.
\n" ); document.write( "you would do so as follows:
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document.write( "p = cat has claws\r\n" );
document.write( "q = cat scratches furniture\r\n" );
document.write( "~p->~q = I\r\n" );
document.write( "q->p = II\r\n" );
document.write( "p->q = III\r\n" );
document.write( "truth table:\r\n" );
document.write( "             p   q   ~p   ~q   ~p->~q   q->p   p->q\r\n" );
document.write( "             T   T    F    F      T       T     T\r\n" );
document.write( "             T   F    F    T      T       T     F\r\n" );
document.write( "             F   T    T    F      F       F     T\r\n" );
document.write( "             F   F    T    T      T       T     T\r\n" );
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\n" ); document.write( "from the truth tables, it appears that ~p->~q is equivalent to q->p because their truth tables are the same.
\n" ); document.write( "that means that I is equivalent to II
\n" ); document.write( "III is not equivalent to either one of them because its truth table is different.
\n" ); document.write( "if we examine the statement, we will see why this is so.
\n" ); document.write( "the statement are, once again:
\n" ); document.write( "I) If the cat does not have claws, then the cat cannot scratch the furniture.
\n" ); document.write( "II) If the cat can scratch the furniture, then the cat has claws.
\n" ); document.write( "III) If the cat has claws, then the cat can scratch the furniture.
\n" ); document.write( "statement II looks like it is the contrapositive of statement I.
\n" ); document.write( "statement I says:
\n" ); document.write( "if no claws, then no scratch furniture.
\n" ); document.write( "statement II says:
\n" ); document.write( "if scratch furniture, then claws.
\n" ); document.write( "if the statement is:
\n" ); document.write( "if no claws, then no scratch furniture
\n" ); document.write( "then the contrapositive to that statement is:
\n" ); document.write( "if scratch furniture, then claws.
\n" ); document.write( "if the statement is:
\n" ); document.write( "if scratch furniture, then claws
\n" ); document.write( "then the contrapositive to that statement is:
\n" ); document.write( "if no claws, then no scratch furniture.
\n" ); document.write( "the statement and its contrapositive are equivalent which means if the statement is true then the contrapositive is also true and vice versa.
\n" ); document.write( "this is the case between statements I and II.
\n" ); document.write( "statement III says:
\n" ); document.write( "if claws, then scratch furniture.
\n" ); document.write( "the contrapositive to this would be.
\n" ); document.write( "if no scratch furniture, then no claws.
\n" ); document.write( "all 3 statements are:
\n" ); document.write( "I = if no claws, then no scratch furniture
\n" ); document.write( "II = if scratch furniture, then claws.
\n" ); document.write( "III = if claws, then scratch furniture.
\n" ); document.write( "the contrapositive to statement III is:
\n" ); document.write( "if no scratch furniture, then no claws
\n" ); document.write( "neither I or II are the contrapositive to statement III, therefore the only equivalent statement are I and II.
\n" ); document.write( "It's a little convoluted, but that's the way it works out.
\n" ); document.write( "Use of the truth tables can make sense of the insensible, assuming you know how to use them.
\n" ); document.write( "p->q is only false if p is true and q is false.
\n" ); document.write( "q->p is only false if q is true and p is false.
\n" ); document.write( "~p->~q is only false if ~p is true and ~q is false.
\n" ); document.write( "~q->~p is only false if ~q is true and ~p is false.
\n" ); document.write( "that's the truth table for the implied statement.l\r
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