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Find three consecutive odd integers such that three times the sum of the first and third is 18 greater than 4 times the second
\n" ); document.write( "Odd numbers are 2 apart from each other:
\n" ); document.write( "1,3,5,7...
\n" ); document.write( "1,1+2,1+2+2,1+2+2+2
\n" ); document.write( ":
\n" ); document.write( "Let the first number be: x
\n" ); document.write( "Then the second will be: x+2
\n" ); document.write( "Then the third will be:x+2+2=x+4
\n" ); document.write( "\"3 times\" means 3*
\n" ); document.write( "\"sum\" means +
\n" ); document.write( "\"is\" means =
\n" ); document.write( "\"18 greater\" means +18
\n" ); document.write( "\"4 times\" means 4*
\n" ); document.write( ":
\n" ); document.write( "3(x+x+4)=4(x+2)+18
\n" ); document.write( "3(2x+4)=4x+8+18
\n" ); document.write( "6x+12=4x+26
\n" ); document.write( "6x-4x+12=4x-4x+26
\n" ); document.write( "2x+12=26
\n" ); document.write( "2x+12-12=26-12
\n" ); document.write( "2x=14
\n" ); document.write( "2x/2=14/2
\n" ); document.write( "x=7
\n" ); document.write( "The first number is: x=7
\n" ); document.write( "The second number is: x+2=7+2=9
\n" ); document.write( "The third number is: x+4=7+4=11
\n" ); document.write( ":
\n" ); document.write( "Sanity Check, does 3 times the sum of the first and third number=4 time the second +18?
\n" ); document.write( "3(7+11)=4(9)+18
\n" ); document.write( "3(18)=36+18
\n" ); document.write( "54=54 Looks valid.
\n" ); document.write( ":
\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "