document.write( "Question 681038:  Lisa will be twice as old as her brother Ralph in 6 years. Lisa was three times as old as Ralph 3 years ago. What are their ages now?
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| Algebra.Com's Answer #422561 by ptaylor(2198)     You can put this solution on YOUR website! Let x=Ralph' age now \n" ); document.write( "And Let y=Lisa's age now\r \n" ); document.write( "\n" ); document.write( "y+6=2(x+6); \n" ); document.write( "y+6=2x+12; \n" ); document.write( "2x-y=-6-----------------eq1 \n" ); document.write( "y-3=3(x-3); \n" ); document.write( "y-3=3x-9; \n" ); document.write( "3x-y=6----------------eq2 \n" ); document.write( "subtract eq1 from eq2: \n" ); document.write( "x=12-----------Ralph's age now \n" ); document.write( "substitute x=12 in eq2 \n" ); document.write( "3*12-y=6 \n" ); document.write( "-y=6-36 \n" ); document.write( "y=30-----------Lisa's age now \n" ); document.write( "CK \n" ); document.write( "30+6=2(12+6) \n" ); document.write( "36=36 \n" ); document.write( "and \n" ); document.write( "30-3=3(12-3) \n" ); document.write( "27=27\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |