document.write( "Question 681038: Lisa will be twice as old as her brother Ralph in 6 years. Lisa was three times as old as Ralph 3 years ago. What are their ages now?
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Algebra.Com's Answer #422561 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=Ralph' age now
\n" ); document.write( "And Let y=Lisa's age now\r
\n" ); document.write( "\n" ); document.write( "y+6=2(x+6);
\n" ); document.write( "y+6=2x+12;
\n" ); document.write( "2x-y=-6-----------------eq1
\n" ); document.write( "y-3=3(x-3);
\n" ); document.write( "y-3=3x-9;
\n" ); document.write( "3x-y=6----------------eq2
\n" ); document.write( "subtract eq1 from eq2:
\n" ); document.write( "x=12-----------Ralph's age now
\n" ); document.write( "substitute x=12 in eq2
\n" ); document.write( "3*12-y=6
\n" ); document.write( "-y=6-36
\n" ); document.write( "y=30-----------Lisa's age now
\n" ); document.write( "CK
\n" ); document.write( "30+6=2(12+6)
\n" ); document.write( "36=36
\n" ); document.write( "and
\n" ); document.write( "30-3=3(12-3)
\n" ); document.write( "27=27\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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