document.write( "Question 681030: what are the dimensions of a parallelogram with the area of 135 with the height = x-3 and base = x+3 \n" ); document.write( "
Algebra.Com's Answer #422552 by stanbon(75887)\"\" \"About 
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what are the dimensions of a parallelogram with the area of 135 with the height = x-3 and base = x+3
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\n" ); document.write( "base*height = 135
\n" ); document.write( "(x+3)(x-3) = 135
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\n" ); document.write( "x^2 - 9 = 135
\n" ); document.write( "x^2 = 144
\n" ); document.write( "x = 12
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\n" ); document.write( "base = x+3 = 15
\n" ); document.write( "height = x-3 = 9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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