document.write( "Question 681030: what are the dimensions of a parallelogram with the area of 135 with the height = x-3 and base = x+3 \n" ); document.write( "
Algebra.Com's Answer #422552 by stanbon(75887) ![]() You can put this solution on YOUR website! what are the dimensions of a parallelogram with the area of 135 with the height = x-3 and base = x+3 \n" ); document.write( "----- \n" ); document.write( "base*height = 135 \n" ); document.write( "(x+3)(x-3) = 135 \n" ); document.write( "----- \n" ); document.write( "x^2 - 9 = 135 \n" ); document.write( "x^2 = 144 \n" ); document.write( "x = 12 \n" ); document.write( "---- \n" ); document.write( "base = x+3 = 15 \n" ); document.write( "height = x-3 = 9 \n" ); document.write( "--------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================== \n" ); document.write( " |