document.write( "Question 680903: SOLUTION: C and Y candy company mixes candy that costs $6.00 per kg with candy that costs $4.50 per kg. How many kg's of each are needed to make a 3kg box that costs $15.00 ?\r
\n" ); document.write( "\n" ); document.write( "you need to do it in a chart
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Algebra.Com's Answer #422506 by lwsshak3(11628)\"\" \"About 
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SOLUTION: C and Y candy company mixes candy that costs $6.00 per kg with candy that costs $4.50 per kg. How many kg's of each are needed to make a 3kg box that costs $15.00 ?
\n" ); document.write( "you need to do it in a chart
\n" ); document.write( "**
\n" ); document.write( ".....$/kg.......kg..........$cost
\n" ); document.write( ".....6.00.........x............6x
\n" ); document.write( ".....4.50........3-x.........4.5(3-x)
\n" ); document.write( ".................... 3.............15
\n" ); document.write( "6x+4.5(3-x)=15
\n" ); document.write( "6x+13.5-4.5x=15
\n" ); document.write( "1.5x=1.5
\n" ); document.write( "x=1
\n" ); document.write( "3-x=2
\n" ); document.write( "kg of $6 candy needed=1
\n" ); document.write( "kg of $4.50 candy needed=2
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